Originally posted by Kerensky97/ NOXCAPE:
Say you put the Anode at the front bumper of the car.
There [b]IS an electrical connection from the rear bumper to the anode in the front bumper through the chassis.
But to complete the circuit you need to have current flow from the anode(front bumper) back to the rear bumper.
This is where the seawater and moist dirt comes in.[/b]
This is where you are incorrect. You have the entire circuit right there in that chunk of iron, otherwise rust wouldn't occur. Consider the following:
The iron in one part of an iron object behaves as an anode, and the iron is oxidized to Fe2+:
Fe(s) -> Fe2+ + 2e-
The electrons produced in this half reaction flow through the metal to another part of the object, which acts as a cathode. Here atmospheric oxygen is reduced in the presence of H+(aq) supplied from H2CO3 formed from dissolved CO2:
O2 + 4H+ = 4e- -> 2H20
THE CIRCUIT IS COMPLETED BY THE MOVEMENT OF IONS THROUGH WATER ON THE SURFACE OF THE IRON. The overall reaction is the sum of the cathode and anode reactions:
2Fe(s) + 02(g) + 4H+ -> 2Fe2+ + 2H2O
The Fe2+ is further oxidized by atmospheric oxygen to rust:
4Fe2+ +O2 + 4H20 -> 2Fe2O3(s) + 8H+
NOW, we have see that the iron corrodes by becoming the anode of an electrochemical cell. However, IF WE CONNECT THE IRON TO A MORE EASILY OXIDIZED METAL SUCH AS ZINC OR MAGNESIUM, THAN THIS METAL BECOMES THE ANODE OF A CELL AND IT CORRODES INSTEAD OF THE IRON.
The Zinc supplies the electrons to the reaction. Now, you being an electrician understand that it doesn't matter how far away the source of those electrons are, as long as they are connected by conductor to what would have been the anode.
You can test this - take two non-galvanized nails, connect them with some copper wiring, wrap some Mg ribbon around one of them (this being the front bumper w/ chunk of Zn) and mist them with some salt water. The Zn will corrode, and the nails will remain non-rusted.
You can continue to argue that this won't occur, but any basic chemistry text will tell you otherwise.
Regards,
Tim