The force of friction acting upon the plane can be determined.

Friction = (coefficient of friction) x (normal force). This means that the force of friction is a coefficiant (usually 1.0-rubber to concrete to 0.1-rubber to ice) that is multiplied times the weight of the airplane (normal force)

So if the weight of the aircraft is 150,000 kg (1,500 kN, kN = kilo Newton, measure of force) and a good guess at the friction of a wheel with no brakes applied was used - Ff=(0.25)x(1,500)= 375 kN. As long as the thrust was more than 375 KN, the plane would beat the resistance of the rolling runway.

If the friction facor was increased by a lot, the force of friction would at some point exceed the force of thrust, and the plane will not move. Essentially, the stickier the belt, the better chance it has of holding the plane back, otherwise it takes off.

Don't make me draw up a free-body diagram.

Edited to correct a spelling mistake