I think we can figure out what would slip from there.
Whatcha think?
I think the drooped tire will slip, even with the pathetic Nissan LSD, as soon as it loses a decent amount of traction, which I think will be long before the revolver reaches it's full droop limit.
I know what you're saying about the increase in traction at the other corners, but it's really only an increase in traction at the other axle, because whatever tire is on the same axle as the revolver shackle, is not going to be able to use the increase with an open diff, or even an LSD, because the drooped will start slipping, and that's the end of the game.
Now we're just splitting hairs. We're just in disagreement with whatever the theoretical value of force it takes to get the truck to move.
We can solve this really quickly, though. Go offroading with Jeff. Park your X on a steep incline, and have him stand behind you and put all his weight against the rear hatch, pushing you uphill. Then let off the brake. If he can push it uphill, then it only takes a few hundred pounds of force to get you moving. If he gets flattened like a pancake, then I was right, and the discussion is over.
(Ironic, isn't it, that in order for you to be right, Jeff has to live. And for me to be right, he has to be smushed. Sorry, Jeff; no offense. It's just the way things worked out.)
![[Spit]](graemlins/spit.gif)